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What are the zeros of the quadratic function f(x) = 6x2 + 12x – 7?

x = –1 – StartRoot StartFraction 13 Over 6 EndFraction EndRoot and x = –1 + StartRoot StartFraction 13 Over 6 EndFraction EndRoot
x = –1 – StartFraction 2 Over StartRoot 3 EndRoot EndFraction and x = –1 + StartFraction 2 Over StartRoot 3 EndRoot EndFraction
x = –1 – StartRoot StartFraction 7 Over 6 EndFraction EndRoot and x = –1 + StartRoot StartFraction 7 Over 6 EndFraction EndRoot
x = –1 – StartFraction 1 Over StartRoot 6 EndRoot EndFraction and x = –1 + StartFraction 1 Over StartRoot 6 EndRoot EndFraction

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