Pb(Câ‚‚H3O2)2 (s) + Hâ‚‚S (g) --> PbS (s) + HCâ‚‚H302 (8)
[unbalanced equation]
Balance this equation, and then calculate how many grams of lead (II) sulfide form when you use 55.11
g of lead (II) acetate and excess (an unlimited amount of) Hâ‚‚S?