Money is invested at two rates of interest. One rate is 8% and the other is 2%. If there is $800 more invested at 8 % than at 2 %. find the amount invested at each
rate if the total annual interest received is $490. Let x = amount invested at 8 % and y = amount invested at 2 %. Then the system that models the problem is
x=y+800
Solve the system by using the method of addition.
0.08x+0.02y = 490

8% is
2% is