A graduate of an engineering economy course has compiled the following set of estimated costs and salvage values for a proposed machine with a first coat of $15,000: however, he has forgotten how to find the most economic life, Your task is to show him how to do this by calculating the equivalent annual coat (EAC) n = 8. given a MARR of 15%. Life (n) Years Estimated End-of-Year Maintenance Estimated Salvage 1 $ 0 $l0,000 2 $ 0 9,000 3 300 7,000 4 300 7,000 5 800 6,000 6 1300 5,000 7 1800 4,000 8 2300 3,000 9 2800 2,000 10 3300 1,000 Remember Calculate only one EAC (for n = 8). You are not expected to actually find the most economical life. Provide answer with as a positive number with two decimal place precision