The form of the partial fraction decomposition of a rational function is given below. 4x 2x² + 12 A (x+5)(x² + 4) x + 5 A = -2 B= 0 C = 4 Now evaluate the indefinite integral. 4x2x² + 12 J dx = 2(-In(x+5)+arctan(x/2))+C (x + 5) (x²+4) = Bx + C x² + 4