Aluminum reacts with bromine to produce aluminum bromide according to the following equation:
2A1 (5) + 3 BI2 (D) -> 2 AlBIs (S)
[unbalanced}
In the lab you perform this reaction using an excess of aluminum and 55.7 grams of bromine. You end up collecting 60.0 grams of product aluminum bromide. What is your percent yield?
Please help me. Thank you so much