- Consider the function f(x) = + 1-3. = Evaluate f at 1 and 2 f(1) = f(2)= From the Intermediate Value Theorem, we may conclude that the equation x + x - 3, has a root somewhere in the interval (1 point) - Consider the function f(x) = 25 - 2 + 3x - 5. Evaluate f at 1 and 2 f(1) = f(2)= From the Intermediate Value Theorem, we may conclude that the equation 25-23 + 3.0 -- 5 = 0, has a root somewhere in the interval (1 point) - Evaluate the following limit. You may enter any real number, "infinity", "-infinity", or "DNE". 4x - 7 lim 10 22 + 3 Limit: 5/4 (1 point) - Evaluate the following limit. You may enter any real number, "infinity", "-infinity", or "DNE". Vt + 4t lim t> 6t - t2 Limit: -2 (1 point) - Evaluate the following limit. You may enter any real number, "infinity", "-infinity", or "DNE". (2x² + 2) lim 24+ (x - 1)'(+ ) Limit: 1/2