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25-05-2023
Mathematics

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Fill in the missing axiom numbers in the following proof that Ou = 0 for every u in V: Ou = (0+0) = 0u + Ou (by Axiom Add the negative of Ou to both sides: Ou + (-Ou) = [Ou + Ou] + (-Ou) (by Axiom Ou+(-0u) = 0u + (Ou + (-Ou)) (by Axiom 0 = Ou + 0 (by Axiom 0 = 0u (by Axiom

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