The AW for Motor A is
The AW for Motor B is.
​(Round to the nearest​ dollar.)
Two electric motors (A and B) are being considered to drive a centrifugal pump. Each motor is capable of delivering 60 horsepower (output) to the pumping operation. It is expected that the motors will
be in use 900 hours per year. If electricity costs $0.07 per kilowatt-hour and 1 hp = 0.746 kW, which motor should be selected if MARR = 9% per year? Refer to the data below. Motor A Motor B $1,400 $800 Initial Cost Electrical Efficiency 0.88 0.55 Annual $60 $95 Maintenance Life 5 years 5 years Click the icon to view the interest and annuity table for discrete compounding when the MARR is 9%