Consider the following system at equiLiBrium where H° = -18.8 kJ/mol, and Kc = 10.5, at 350 K. 2 CH₂Cl₂ (g) → CH₄ (g) + CCl₄ (g) When 0.37 moles of CH₂Cl₂ (g) are removed from the equiLiBrium system at constant temperature, What will be the effect on the concentrations of CH₄ (g) and CCl₄ (g)?
1) The concentration of CH₄ (g) will increase and the concentration of CCl₄ (g) will decrease.
2) The concentration of CH₄ (g) will decrease and the concentration of CCl₄ (g) will increase.
3) The concentrations of both CH₄ (g) and CCl₄ (g) will decrease.
4) The concentrations of both CH₄ (g) and CCl₄ (g) will increase.