demilade9813 demilade9813

23-01-2024
Mathematics

contestada

The slope of normal to the curve x3=8a2y,a >0 at a point in the first quadrant is −2/3 , then point is
A) (2a,-a)
B) (2a, a)
C) (a, 2a)
D) (a,a)

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