bosspuppy6151 bosspuppy6151 23-01-2024 Physics contestada At any instant, the position of a particle of mass 200 gm is (10t²i + 5t³j). If the momentum of the particle at any instant is (xi + 12j) kgm/s, then the value of x will be:a) 20tb) 10t²c) 30td) 15t