3CaCI2(aq)+ 2Na(PO4)(aq)-----> Ca3(PO4)2(s) + 6NaCl (aq) CaCI2:110.0 Na3(PO4) 163.9 Ca3(PO4)2 310.2 NaCL 58.44 Suppose 163.9 g of Na3(PO4) in solution mixed with suffcient CaCL2 in solution yields 116g of Ca(PO4)2(s) what is the % yield of Ca3(PO4)s(s)