For the following reaction, determine how many grams of Zn3(PO4)2 will be produced by 2.12 grams of (NH4)3PO4:

[ 3 {ZnCl}₂ + 2 ({NH}₄)₃ {PO}₄ rightarrow {Zn}₃({PO}₄)₂ + 6 {NH}₄{Cl} ]

A) 0.61 g
B) 0.456 g
C) 2.74 g
D) 5.48 g