When 1 mole of N₂ and 1 mole of H₂ is enclosed in 3L vessel and the reaction is allowed to attain equilibrium,it is found that at equilibrium there is ′x′ mole of H₂. The number of moles oh NH₃ would be:
a. [2(1+x)]/3
b. [2(1−x)]/3
c. 2x/3
d. (1−x)/3