Calculate the electromotive force (emf) of the following cell at 298 K:

2Cr(s)∣3Fe²⁺(0.1M)∣2Cr³⁺(0.01M)∣3Fe(s)

Given: ECr³⁺/Cr0​=−0.74V and EFe²⁺/Fe0​=−0.44V; log10=1,log₂=0.3010