kafledebaki7 kafledebaki7 26-02-2024 Mathematics contestada prove that:[tex] \frac{1}{a {}^{2} + 2ab + b {}^{2} } + \frac{1}{a {}^{2} - 3a + 2} [/tex]is equal to [tex] \frac{2a + 1}{(a - 1)( a+ 3)(a - 2)} [/tex]