Using the equations n₂(g) + 3 H₂(g) → 2 NH₃(g) ΔH° = -91.8 kJ/mol C(s) + 2 H₂(g) → CH₄(g) ΔH° = -74.9 kJ/mol H₂(g) + 2 C(s) + N₂(g) → 2 HCN(g) ΔH° = 270.3 kJ/mol Determine the enthalpy (in kJ/mol) for the reaction CH₄(g) + NH₃(g) → HCN(g) + 3 H₂(g).
a) -15.4
b) -19.1
c) -10.2
d) -8.7