CaCO₃(s)+2HCl(aq)⟶CaCl₂(aq)+H₂O(l)+CO₂(g)
how many grams of cacl₂ can be obtained if 38.7 g hcl is allowed to react with excess caco3?
O 58.9 g cacl₂
O 0.531 g cacl₂
O 236 g cacl₂
O 118 g cacl₂