Triangle ABC has vertices A(-3, 1), B(-3, 4), and C(-7, 1).
Part a: If ∆ABC is translated according to the rule (x, y) → (x - 3, y + 4) to form ∆A'B'C', how is the translation described with words?
Part b: Where are the vertices of ∆A'B'C' located?
Part c: Triangle A'B'C' is rotated 180° counterclockwise about the origin to form ∆A"B"C". Is ∆ABC congruent to ∆A"B"C"? Give details to support your answer.