From the experimentally determined mass lost or gained at the electrode and the experimentally determined number of coulombs, calculate the equivalent weight of copper and then the valence of copper using the atomic mass of copper.
Wthat is the question, please look at my answer and see what is wrong, I need an equivalent weight of around 30 but I am getting an equivalent weight of under 1.
Equivalent weight = change mass (-) electrode + change mass (+) electrode/2 then divide by number of faradays.
(0.0299 g + (-0.0283 g))/2 = 0.0008 g
0.0008 g / 0.001 faradays = 0.8 grams for equivalent weight (when it should be around 30)