Your teacher forgot to check which chemicals were available before planning this lab. The only solution of NaOH available was 0.75 M. How would this affect the amount of NaOH needed to neutralize the excess acid in your experiment? Provide both a written explanation as well as a photograph of the calculation of the new volume of base titrated below. Use the moles of excess acid (Q5 in the Calculations section above) as the starting point of your calculation.

481 * 1/36.46084 = 13.19 moles of excess acid