Answer: The new pressure will be 101.46 kPa.
Explanation:
To calculate the new pressure, we use the equation given by Gay-Lussac Law. This law states that pressure is directly proportional to the temperature of the gas at constant volume.
The equation given by this law is:
[tex]\frac{P_1}{T_1}=\frac{P_2}{T_2}[/tex]
where,
[tex]P_1\text{ and }T_1[/tex] are initial pressure and temperature.
[tex]P_2\text{ and }T_2[/tex] are final pressure and temperature.
We are given:
By using conversion factor: [tex]T(K)=T(^oC)+273[/tex]
[tex]P_1=108kPa\\T_1=41^oC=314K\\P_2=?kPa\\T_2=22^oC=295K[/tex]
Putting values in above equation, we get:
[tex]\frac{108kPa}{314K}=\frac{P_2}{295K}\\\\P_2=101.46kPa[/tex]
Hence, the new pressure will be 101.46 kPa.
If the temperatue of the sealend plastic container changes from 41°C to 22°C so pressure decreases from 108 kPa to 101.46 kPa.
Gay-Lussac Law of gases states that at constant volume of the sample pressure of the gas is directly proportional to the
(in Kelvin) of the gas, and it is represented as:
P₁/T₁ = P₂/T₂, where
P₁ = initial pressure = 108 kPa
T₁ = initial temperature = 41 degree C = 314K
P₂ = final pressure = ?
T₂ = final temperature = 22 degree C = 295K
On putting values, we get
P₂ = (108)(295) / (314) = 101.46 kPa
Hence resultant pressure is 101.46 kPa.
To know more about Gay-Lussac Law, visit the below link:
https://brainly.com/question/24002551
