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If KJ = 33 and KN = [tex] 6\sqrt{10} [/tex] , calculate the length of GJ.
1. 27
2. [tex] 6\sqrt{161} [/tex]
3. [tex] 3\sqrt{161} [/tex]
4. 54
also please show work on how you found your answer

If KJ 33 and KN tex 6sqrt10 tex calculate the length of GJ 1 27 2 tex 6sqrt161 tex 3 tex 3sqrt161 tex 4 54 also please show work on how you found your answer class=

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Blitztiger
KJ is the hypotenuse of the right triangle KJN, therefore:KJ^2 = KN^2 + JN^233^2 = (6sqrt10)^2 + JN^21089 = 360 + JN^2JN^2 = 729JN = 27
The figure is a trapezoid, since GH // JI, and MN is perpendicular to HI. Therefore GN = JN = 27. The length of GJ = 54.

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