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The elevation​ E, in​ meters, above sea level at which the boiling point of a certain liquid is t degrees Celsius is given by the function shown below. At what elevation is the boiling point 89.5degrees​? and 90degrees​?

E(t)= 1100(90-t)+520(90-t)^2

Respuesta :

Blitztiger
For T = 89.5 degrees C:
E(t) = 1100(90 - 89.5) + 520(90 - 89.5)^2= 1100(0.5) + 520(0.5)^2= 550 + 130= 680 m
For T = 90 degrees C:
E(t) = 1100(90 - 90) + 520(90 - 90)^2= 0 + 0= 0 m (meaning that boiling point is 90 degrees C at ground level)

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