Using kinematic equations, we can solve for his final velocity and the distance he traveled.
Since he is initially at rest, then the initial velocity is 0m/s. We also know that he is in free-fall, so his acceleration is -9.80m/s^2.
Using this equation, we can solve for final velocity.
[tex]v_{f} = v_{0} +at[/tex]
Plug in known values:
[tex]v_{f} = 0 - (9.8 \frac{m}{s^2} )(2.8s)
v_{f} = -27.44\frac{m}{s} [/tex]
Next using this equation, we can solve for our displacement
[tex]d = v_{0}t + \frac{1}{2}gt^2[/tex]
Plug in known values, we get:
[tex]d = 0 - \frac{1}{2}(9.80 \frac{m}{s^2})(2.8s)^2
d=-38.416m[/tex]
