Respuesta :
For this case we have the following vector:
v = -6i.
Using product point we have:
v.v = (-6i.). (- 6i)
v ^ 2 = 36
Then, clearing the module we have:
v = root (36)
v = 6
Answer:
The module of the vector is given by:
v = 6
D. 6
v = -6i.
Using product point we have:
v.v = (-6i.). (- 6i)
v ^ 2 = 36
Then, clearing the module we have:
v = root (36)
v = 6
Answer:
The module of the vector is given by:
v = 6
D. 6