Answer:
The measure of arc JH is 44°.
Step-by-step explanation:
Given information: ∠JOH = 27° and arc NML = 98°.
If two chord intersect outside the circle, then
[tex]\frac{\text{major arc-minor arc}}{2}=\text{Angle between of chords}[/tex]
From the given figure it is clear that the major arc is NML and the minor arc is JH.
Let the measure of arc JH be x.
[tex]\frac{\text{arc NML-arc JH}}{2}=\angle JOH[/tex]
[tex]\frac{98-x}{2}=27[/tex]
[tex]98-x=54[/tex]
[tex]-x=-44[/tex]
[tex]x=44[/tex]
Therefore the measure of arc JH is 44°.
