We can use the heat equation,
Q = mcΔT
Where,
Q = the amount of energy transferred (J)
m = the mass of the substance (kg)
c = the specific heat (J g⁻¹ °C⁻¹)
ΔT = the temperature difference (°C).
According to the given data for the substance,
Q = 300 J
m = 267 g
c = ?
ΔT = 12 °C
From substitution,
300 J = 267 g x c x 12 °C
c = 0.0936 J g⁻¹ °C⁻¹
Hence, specific heat of the given substance is 0.0936 J g⁻¹ °C⁻¹.
