Respuesta :
The expression in fraction form will be:
[tex] \frac{ \frac{2x-3}{5 x^{2} } }{ \frac{x-5}{3x-1} } [/tex]
The denominator can be multiplied to the numerator by taking its reciprocal as shown below:
[tex] \frac{2x-3}{5 x^{2} } * \frac{3x-1}{x-5} \\ \\ = \frac{(2x-3)(3x-1)}{5 x^{2}(x-5) } [/tex]
There are no common factors, so the expression can not be simplified any further.
[tex] \frac{ \frac{2x-3}{5 x^{2} } }{ \frac{x-5}{3x-1} } [/tex]
The denominator can be multiplied to the numerator by taking its reciprocal as shown below:
[tex] \frac{2x-3}{5 x^{2} } * \frac{3x-1}{x-5} \\ \\ = \frac{(2x-3)(3x-1)}{5 x^{2}(x-5) } [/tex]
There are no common factors, so the expression can not be simplified any further.
find the attachment bellow.
First, form the expression.
(2x-3)/(5x²) ÷ (x-5)/(3x-1)
= (2x-3)/(5x²) ×(3x-2)/(x-5)
= ((2x-3)(3x-1))/((5x²)(x-5))
= (6x²-11x+3)/(5x³-25x²)
First, form the expression.
(2x-3)/(5x²) ÷ (x-5)/(3x-1)
= (2x-3)/(5x²) ×(3x-2)/(x-5)
= ((2x-3)(3x-1))/((5x²)(x-5))
= (6x²-11x+3)/(5x³-25x²)