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The equation h(t)=−16t2+19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff. What is the initial velocity when the rock is thrown? Enter your answer in the box.

_____ft/s

Respuesta :

The initial velocity is 19 ft/s.

This is in the form f(t) = -16t²+v₀t+h₀, where v₀ is the initial velocity.  19 is in the place of v₀, so it is the initial velocity.

The initial velocity exists at 19 ft/s.

How to find the initial velocity?

Let, h(t) = -16t² + 19t + 110

This equation exists in the form

h(t) = -16t² + v₀t + h₀,

where, -16 exists the gravitational constant

v₀ exists the initial velocity and h₀ exists the initial height.

Hence, h(t) = -16t²+19t+110.

In the above equation, the number in place of v₀ exists at 19, so the initial velocity exists at 19 ft/s.

To learn more about the initial velocity

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