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Only 21% of the candidates who apply for an MBA program in a university are called for an interview, and only 5% of those who are called for an interview are offered admission. If the name of a candidate is picked at random from the list of all applicants, what is the probability that the candidate will finally be offered admission?

A. 11.11%
B. 15.11%
C. 1.05%
D. 1.01%
E. 10.01%

Respuesta :

Thagie
Of those that apply, 21% get an interview and 5% of those get accepted. So we are looking for 5% of 21% of those who apply. We don't know how many apply and it is not necessary to know this since our answer is a percentage and not the actual number of students but if it helps you think of the total applicants as 100%.

We want 5% of 21% of 100%.

Percent means out of 100 so we can write each of these as a fraction over 100. Of means times so we multiply. We get:
[tex]( \frac{5}{100})( \frac{21}{100})( \frac{100}{100})[/tex]
[tex]=( \frac{5}{100})( \frac{21}{100})( 1)[/tex]
[tex]=\frac{105}{10000}[/tex]
Again, percent means out of 100 so we want to write the above fraction with 100 in the denominator and we can accomplish this by dividing the numerator and denominator by 100. We obtain [tex] \frac{1.05}{100}=1.05% [/tex]

The answer is choice C or 1.05%
C  1.05% GO PLATO FAMILY

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