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To approach the runway, a pilot of a small plane must begin a 10* descent starting from a height of 1,790 feet above ground. To the nearest tenth of a mile, how many miles from the runway is the airplane at the start of this approach? A. 2.0 mi B. 0.3 Mi C. 1.7 mi D. 10,308.2 mi

Respuesta :

since there are 5280 feet in 1 mile, in 1790 feet, there are 1790/5280 miles, or about 0.339 miles.

check the picture below.

make sure your calculator is in Degree mode.
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Answer:

2.0 mi

Step-by-step explanation:

x = depression

[tex]sin10° = \frac{1790ft}{x}[/tex]  Use sine ratio.

[tex]x = \frac{1790ft}{sin10°}[/tex] Use calculator to find sin10° and simplify for x.

[tex]x = \frac{1790ft}{0.17364817766693034885171662676931}[/tex]

[tex]x = 10,308.199164827104029827422425645ft[/tex]

*NEED TO CONVERT FT TO MILES*

1 mile = 5280 ft. Substitute ft for mi

[tex]\frac{10,308.199164827104029827422425645 ft }{5280ft} = 1.9523104478839212177703451563722 mi[/tex]

= 2.0 mi rounded to nearest tenth

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