Respuesta :
Perimeter = 2L + 2W → 240 = 2L + 2W → 120 = L + W → 120-L = W
Area = L x W → Area = L(120-L) → Area = 120L - L²
Find the derivative: dA/dL = 120 -2L → 0 = 120 - 2L → L = 60
Area = 120L - L² = 120(60) - (60)² = 7200 - 3600 = 3600
The maximum area is 3600 yds²
Area = L x W → Area = L(120-L) → Area = 120L - L²
Find the derivative: dA/dL = 120 -2L → 0 = 120 - 2L → L = 60
Area = 120L - L² = 120(60) - (60)² = 7200 - 3600 = 3600
The maximum area is 3600 yds²
The largest total area that can be enclosed is 3600 yards².
A rectangle is a 4-sided shape that is made up of a length and width.
Area of a rectangle = length x width
Perimeter of a rectangle = 2(length + width)
240 = 2(l + b)
120 = l + b
The second step is to determine the dimensions of a rectangle that would be equal to 120
pairs of dimensions:
60cm x 60 = 3600
50 x 70 = 3500
40 x 80 = 3200
30 x 90 = 2700
20 x 100 = 1200
1 x 119 = 119
To learn more about the perimeter of a rectangle, please check: brainly.com/question/18793958
