Initial upward velocity= 36 m/s
acceleration due to gravity= 9.8 m/s²
Concept:
As, the acceleration is constant ( acceleration is only due to gravity) so we use the equations of constant acceleration for this question:
As, given
y=y° + v*t +1/2(a)(t²)
As, the initial and final height of the football is ground so change in distance covered in the vertical direction is zero.
y-y°=v*t + 1/2(a)(t²)
0= 36 t + 1/2(-9.8)(t²)
-ve sign because force is downward.
0= 36 t - 4.9 t²
Option B is correct
