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A 3.0 L container holds a sample of hydrogen gas at 300 K and 100 kPa. If the pressure increases to 300 kPa and the volume remains constant, what will the temperature be?
600 K
900 K
300 K
100 K

Respuesta :

kenmyna
if the pressure  increases  to 300 KPa and  the volume  remain constant  the temperature  will be 
                              900K

it is calculated  using the gays lussac law formula that is P1/T1=P2/T2
P1= 100Kpa
p2=300Kpa
T1=300k
T2=?
by making T2 the subject  of the formula T2 =P2T1/P1

=300KPa x300 k/100 kpa = 900 K

If the pressure increases from initial to 300 kPa and the volume remains constant, 900K will the temperature be.

How we calculate the temperature by using the ideal gas equation?

We can calculate the required pressure by using the ideal gas equation as :

P₁/T₁ = P₂/T₂, where

P₁ = initial pressure of hydrogen gas = 100 kPa

T₁ = initial temperature of hydrogen gas = 300K

P₂ = final pressure of hydrogen gas = 300kPa

T₂ = final temperature of hydrogen gas = ?

In this question volume is constant, now on putting all these values in the above equation we get

T₂ = (300×300) / 100 = 900K

Hence, 900K is the required temperature.

To know more about ideal gas equation, visit the below link:

https://brainly.com/question/20348074

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