Answer:
2.0 miles.
Step-by-step explanation:
Let x be the distance from the runway and airplane at the start of this approach.
We have been given that to approach the runway, a pilot of a small plane must begin a 10 degree descent from a height of 1790 feet above the ground.
We will use sine to solve our given problem as sine relates opposite side of a right triangle to its hypotenuse.
[tex]\text{sin}=\frac{\text{Opposite}}{\text{Hypotenuse}}[/tex]
Upon substituting our given values in above formula, we will get:
[tex]\text{sin}(10^{\circ})=\frac{1790}{x}[/tex]
[tex]x=\frac{1790}{\text{sin}(10^{\circ})}[/tex]
[tex]x=\frac{1790}{0.173648177667}[/tex]
[tex]x=10308.1991648[/tex]
To convert the distance into miles, we will divide our distance in feet by 5280 as one mile equals to 5280 feet.
[tex]x=\frac{10308.1991648}{5280}[/tex]
[tex]x=1.95231044788[/tex]
Upon rounding our answer to the nearest tenth of a mile we will get,
[tex]x\approx 2.0[/tex]
Therefore, the airplane is approximately 2.0 miles away from the runway at the start of this approach.
Answer:
2.0 Miles
Step-by-step explanation:
If you see on another post that the answer is .3 that is incorrect
