Respuesta :
The power used by an electrical device can be written as
[tex]P= \frac{V^2}{R} [/tex]
where V is the potential difference applied to the device and R is the electrical resistance of the device.
In this problem, the power used is P=590 W and the device operates at voltage of V=120 V, therefore we can re-arrange the previous equation to calculate its resistance:
[tex]R= \frac{V^2}{P}= \frac{(120V)^2}{590 W}= 24.4 \Omega[/tex]
[tex]P= \frac{V^2}{R} [/tex]
where V is the potential difference applied to the device and R is the electrical resistance of the device.
In this problem, the power used is P=590 W and the device operates at voltage of V=120 V, therefore we can re-arrange the previous equation to calculate its resistance:
[tex]R= \frac{V^2}{P}= \frac{(120V)^2}{590 W}= 24.4 \Omega[/tex]
Answer:
24.4 Ω
Explanation:
Thinking process:
The equation relating the power and voltage is given as:
[tex]R = \frac{V^{2} }{P}[/tex]
Given that:
Power = 590 W
Voltage = 120 V
The power therefore will be:
[tex]P = \frac{(120)^{2} }{590}[/tex]
= 24.4 Ω