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The student council is sponsoring a concert as a fundraiser. Tickets are $3 for students and $5 for adults. The student council wants to raise at least $1,000. If 200 students attend how many adults must attend for them to get to their goal. write and solve an inequality

Respuesta :

3S+5A≥1000
3(200)+5A≥1000
600+5A≥1000
-600        -600
5A≥400
-----------
      5

A≥80
so 80 adults

Answer:

There must attend at least 80 adults to raise at least $1,000.

Step-by-step explanation:

Givens

  • Tickets are $3 for students and $5 for adults.
  • They want to raise at least $1,000. (Restriction).
  • 200 students attended.

Let's call [tex]S[/tex] students and [tex]A[/tex] adults.

We know the benefits are restricted as

[tex]3S+5A\geq 1000[/tex]

Because, they want to raise AT LEAST $1000, that's the minimum amount possible.

Now, we know that [tex]S=200[/tex], replacing this value and solving for adults, we have

[tex]3S+5A\geq 1000\\3(200)+5A\geq 1000\\600+5A\geq 1000\\5A\geq 1000-600\\5A\geq 400\\A \geq \frac{400}{5}\\ A\geq 80[/tex]

Therefore, there must attend at least 80 adults to raise at least $1,000.

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