contestada

What are the components of vector B if its magnitude is 18 m and makes an angle of 112° with the +x-axis?

Bx = −6.74 m, By = 16.7 m

Bx = 6.74 m, By = −16.7 m

Bx = 16.7 m, By = −6.74 m

Respuesta :

skyluke89
Calling B=18 m the magnitude of the vector, its components on the x- and y- axis are given by:
[tex]B_x = B \cos \theta =(18 m)(\cos 112^{\circ})=-6.74 m[/tex]
[tex]B_y = B \sin \theta = (18 m)(\sin 112^{\circ}) = 16.7 m[/tex]
Therefore, the correct answer is the first one:
Bx = −6.74 m, By = 16.7 m

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