Respuesta :
The smallest–largest ordering of sides is the same as the smallest–largest ordering of angles.
Since angle G is the largest angle, the opposite side, JH, is longest.
The order of side lengths from longest to shortest is JH, HG, GJ.
Since angle G is the largest angle, the opposite side, JH, is longest.
The order of side lengths from longest to shortest is JH, HG, GJ.
The order of the side lengths from longest to shortest is
JH > GH > GJ
Given :
In triangle GHJ the measure of angle G equals [tex]110^\circ[/tex], the measure of angle J equals [tex]40^\circ[/tex], and the measure of angle H equals [tex]30^\circ[/tex].
G is an angle opposite to side JH.
Solution :
Given that G is an angle opposite to side JH and G is the largest angle therefore the side JH opposite to angle G is the longest side.
Also given that angle H is [tex]30^\circ[/tex] which is the smallest angle therefore the side GJ opposite to angle H is the shortest side.
Therefore the order of the side lengths from longest to shortest is
JH > GH > GJ
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https://brainly.com/question/13954458