Did you get the answer to Part B? we have the same problem.
The answer for Part A is this,
y=2x^2-15. and y=3x-6
2x^2-15=3x-6
(Add 15 to both sides)
2x^2-3x-9=0
(Factor)
(2x+3)(x-3)
(Set equal to zero on both sides to solve)
2x+3=0 and x-3=0
Subtract 3 from both sides for the first equation.
Add 3 to both sides in the second equation.
2x=-3 and x=3
Divide by 2 on both sides for the first equation ONLY.
To get x=-3/2
THE TWO X VALUES ARE
X=-3/2 and X=3