a 10 foot ladder is leaning up against a wall. The base of the ladder is 2 feet from the base of the building. How far up the building does the ladder fall?
see the picture attached to better understand the problem
we know that applying the Pythagoras Theorem AC²=AB²+BC² AC=10 ft BC=2 ft AB=? AB²=AC²-BC²-----> 10²-2²-----> 100-4----> AC²=96 AC=√96 ft------> AC=9.80 ft
