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PLZ NEED HELP WILL MARK BRAINLIEST IF RIGHT!!!!!
The figure below shows a shaded rectangle inside a large rectangle:

PICTURE BELOW

If you choose a point inside the large rectangle, what is the probability that it is not inside the shaded rectangle?

24%
27%
46%
54%

PLZ NEED HELP WILL MARK BRAINLIEST IF RIGHT The figure below shows a shaded rectangle inside a large rectangle PICTURE BELOW If you choose a point inside the la class=

Respuesta :

musiclover10045
Area of large rectangle = 10 * 5 = 50 square units

Area of shaded rectangle = 9 * 3 = 27 square units

the shaded rectangle is 27/50 = 54% of the larger rectangle

100% - 54% = 46% chance of not being in the shaded rectangle
nooooo5
Area of large rectangle = L × B

= 10 unit × 5 unit

= 50 sq. unit.

Now,

Area of Shaded region = L × B

= 9 unit × 3 unit

= 27 sq.unit.


Ar. of unshaded region = 50 sq.unit - 27 sq.unit

= 23 sq.unit.


Favourable outcome = 23 sq. unit

Total outcome = 50 sq.unit


P = 23 sq. unit ÷ 50 sq. unit

= 23 / 50.

Let 50 of x% is 23.


50 × x / 100 = 23

x/2 = 23

x = 23 × 2

x = 46.

= 46%.

The required answer is option c.46%.

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