For this case we have an equation of the form:
h (t) = (1/2) * a * t ^ 2 + vo * t + h0
Where,
a: acceleration
vo: initial speed
h0: initial height
t: time
We have then that the equations:
h (t) = - 16t ^ 2 + 19t + 110
Therefore, the initial velocity is given by:
vo = 19 feet / s
Answer:
The initial velocity when the rock is thrown is:
vo = 19 feet / s
