I will mark Brainliest
A cuboctahedron is a convex polyhedron with 12 vertices and 14 faces. A snub cube is a convex polyhedron with 24 vertices and 38 faces.
How do the number of edges of a cuboctahedron and a snub cube compare?
Using Euler's formula: F+V-E = 2A cuboctahedron will have 14 + 12 - E = 2, and E = 24 edges.A snub cube will have 38 + 24 - E = 2, so E = 60 edges. Therefore, a snub cube has more edges than (in fact, 2.5x as many edges as) a cuboctahedron.
