At which values of x does the function F(x) have a vertical asymptote ? Check all that apply. (Picture provided )

Answer:
The vertical asymptote of given function is x=-2 and x=-3
C and D are correct.
Step-by-step explanation:
Given: [tex]F(x)=\dfrac{1}{7(x+2)(x+3)}[/tex]
Vertical Asymptote: It is value of x where denominator of function is 0.
It is vertical line of function where graph touches at infinity.
In given function denominator factors are (x+2)(x+3)
We will set each factor to 0 and solve for x
x+2=0 and x+3=0
x=-2 and x=-3
Hence, The vertical asymptote of given function is x=-2 and x=-3