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Suppose that a dominant allele (P) codes for a polka-dot tail and a recessive allele (p) codes for a solid colored tail. If two heterozygous individuals with polka-dot tails mate, what's the probability of the phenotype and genotype combinations of the offspring?
A. 75 percent chance of a polka-dot tail and 25 percent chance of a solid colored tail (25 percent PP; 50 percent Pp; 25 percent pp)
B. 75 percent chance of a polka-dot tail and 25 percent chance of a solid colored tail (75 percent Pp; 25 percent pp)
C. 25 percent chance of a polka-dot tail and 75 percent chance of a solid colored tail (25 percent PP; 50 percent Pp; 25 percent pp)
D. 50 percent chance of a polka-dot tail and 50 percent chance of a solid colored tail (50 percent PP; 50 percent pp)

Respuesta :

AlpenGlow
Using a Punnett Square you can solve this. If two heterozygous individuals with polka-dot tails mate then both their genotype would be Pp. The Punnett square will then look like this:

     P     p 
P  PP  Pp
p  Pp   pp

Now if you look at the square, you have the following genotype and phenotype combinations:

PP = 1 out of 4 = 25% : Homozygous polka-dot.
Pp = 2 out of 4 = 50%: Heterozygous polka-dot
pp = 1 out of 4 = 25% Homozygous solid color

With that the answer would then be A. 75 percent chance of a polka-dot tail and 25 percent chance of a solid colored tail (25 percent PP; 50 percent Pp; 25 percent pp).

Answer:

Explanation:

75 percent chance of a polka-dot tail and 25 percent chance of a solid colored tail (25 percent PP; 50 percent Pp; 25 percent pp).

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