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I NEED ANSWER ASAP!!! PLEASE HELP!!! A shot put is thrown upward with a velocity of 35 ft./sec. at a height of 4 ft. and an angle of 40°. How long will it take for the shot put to be a horizontal distance of 40 ft. from the person throwing it? Acceleration due to gravity is 32 ft/s^2. Round your answer to the nearest hundredth.

Respuesta :

The horizontal component of the velocity of the shot is 35 cos 40 ft/sec which is constant
Therefore:-
Velocity = distance / time
35 cos 40  = 40 / t

t = = 40 / 35cos40  =  1.49 seconds to nearest hundredth

shubhamchouhanvrVT

The time taken by the shotput will be equal to 1.49 seconds.

What is Velocity?

Velocity is defined as the ratio of the time distance travelled by the body to the time taken by the body to cover the distance.

Given that:-

  • A shot put is thrown upward with a velocity of 35 ft./sec. at a height of 4 ft. and an angle of 40°.
  • How long will it take for the shot put to be a horizontal distance of 40 ft. from the person throwing it?

The horizontal component of the velocity of the shot is:

35 cos 40 ft/sec

Therefore:-

Velocity = distance / time

35 cos 40  =   40 / t

t  = 40 / 35cos40  

t     =   1.49 seconds

Therefore the time taken by the shotput will be equal to 1.49 seconds.

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