A college graduate expects to earn a salary of $50,000 during the first year after graduation and receive a 3% raise every year after that. What is the total income he will have received after ten years?

Respuesta :

For this case we have a function of the form:
 y = A * (b) ^ t
 Where,
 A: initial amount
 b: growth rate
 t: time
 Substituting values we have:
 y = 50000 * (1.03) ^ t
 For 10 years we have:
 y = 50000 * (1.03) ^ 10
 y = 67195.81897 $
 Answer:
 the total income he will have received after ten years is:
 y = 67195.81897 $

By applying formula of sum of GP we got that the total income he will have received after ten years is $573194

What is a sequence ?

A sequence is collection of numbers with a particular pattern.

here given that A college graduate expects to earn a salary of $50,000 during the first year after graduation and receive a 3% raise every year after that

Hence this is an GP with first term 50,000 and common ratio 1.03

Hence total income he will have received after ten years = sum of 10 terms of GP

[tex]=\frac{a(r^{10}-1)}{r-1}[/tex]

[tex]=\frac{50000(1.03^{10}-1)}{1.03-1} \\\\=50000\times11.4638793\\\\=573193.965\\\\\approx 573194[/tex]

By applying formula of sum of GP we got that the total income he will have received after ten years is $573194

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